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9x^2=-99x
We move all terms to the left:
9x^2-(-99x)=0
We get rid of parentheses
9x^2+99x=0
a = 9; b = 99; c = 0;
Δ = b2-4ac
Δ = 992-4·9·0
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9801}=99$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-99}{2*9}=\frac{-198}{18} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+99}{2*9}=\frac{0}{18} =0 $
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